About 消除泡泡鸟
一旦开始 根本停不下来
一款风靡全球的游戏,蝉联很多国家游戏排行榜第一
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游戏玩法
至少2个以上一样颜色的方块儿连在一起
点击以后可以消除 没有时间限制
过关需要达到响应目标分数
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得分方法
谨记一下秘籍 会助让您轻松创高分
秘籍1
分数 = 消除的方块数*消除的方块数 * 5
比如:
消除2个方块 得分 = 2 * 2 * 5 = 20分
消除3个方块 得分 = 3 * 3 * 5 = 45分
…
消除10个方块 得分 = 10 * 10 * 5 = 500分
….
消除20个方块 得分 = 20 * 20 * 5 = 2000分
秘籍2
剩余方块儿在10个以下时 会获得分数奖励
剩余奖励 = 2000 - 剩余方块数 * 剩余方块数 * 20
剩余 10 个方块 = 2000 - 10 * 10 * 20 = 0
剩余 9 个方块 = 2000 - 9 * 9 * 20 = 380
剩余 8 个方块 = 2000 - 8 * 8 * 20 = 720
…
剩余 2 个方块 = 2000 - 2 * 2 * 20 = 1920
剩余 1 个方块 = 2000 - 1 * 1 * 20 = 1980
全部消除方块儿 奖励得分 = 2000 - 0 * 0 * 20 = 2000
------------------------------ Simply can not stop once you start
A popular game worldwide, won the first game list in many countries
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Gameplay
At least two or more different colored squares child together
No time limit can be eliminated after clicking
Clearance needed to reach the target score response
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Method of Scoring
Cheats will help remember what allows you to easily create high scores
Cheats 1
Score = number of boxes to eliminate the box number * eliminate * 5
For example:
Eliminate two box score = 2 * 2 * 5 = 20 points
Eliminate three box score = 3 * 3 * 5 = 45 points
...
Eliminate 10 box score = 10 * 10 * 5 = 500 points
....
Eliminate 20 box score = 20 * 20 * 5 = 2000 points
2 Cheats
The remaining boxes in 10 children will get points when the following awards
The remaining awards = 2000 - the number of the remaining boxes remaining box number * 20 *
The remaining 10 boxes = 2000 - 10 * 10 * 20 = 0
The remaining nine boxes = 2000 - 9 * 9 * 20 = 380
The remaining eight boxes = 2000 - 8 * 8 * 20 = 720
...
The remaining two boxes = 2000 - 2 * 2 * 20 = 1920
The remaining 1 box = 2000 - 1 * 1 * 20 = 1980
Total elimination of child reward box score = 2000 - 0 * 0 * 20 = 2000
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